Equilibrium - Result Question 66

####69. pH of a saturated solution of Ca(OH)2 is 9 . The solubility product (Ksp) of Ca(OH)2 is: [2019]

(a) 0.510−15

(b) 0.2510−10

(c) 0.12510−15

(d) 0.510−10

Show Answer

Solution:

  1. (a) Ca(OH)2→Ca2++2OH− pH=9,pOH=14−9=5

[OH]=10−5

[Ca2+]=10−52

Ksp=[Ca2+][OH−]2=(10−52)×(10−5)2

=0.5×10−15

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