Equilibrium - Result Question 58
####60. The $pH$ value of a $10 M$ solution of $HCl$ is [1995]
(a) less than 0
(b) equal to 0
(c) equal to 1
(d) equal to 2
Topic 4: Ionisation of Weak Acids and Bases and Relation between $K_a$ and $K_b$
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Solution:
- (a) Molarity $(M)=10 M$. $HCl$ is a strong acid and it is completely dissociated in aqueous solutions as : $HCl(10) \rightarrow H^{+}(10)+Cl^{-}$.
So, for every moles of $HCl$, there is one $H^{+}$. Therefore $[H^{+}]=[HCl]$ or $[H^{+}]=10$.
$pH=-\log [H^{+}]=-\log [10]=-1$.
