SATHEE: Equilibrium - Result Question 54

Equilibrium - Result Question 54

####56. Conjugate acid of $N H_{2}^{-}$ is :

(a) $N H_{4}^{+}$

(b) $N H_{3}$

(d) $N H$

[2000]

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Solution:

(b) Because $N H_{3}$ after losing a proton $(H^{+})$ gives $N H_{2}^{-}$

$N H_{3} + H_{2} O \to N H_{2}^{-} + H_{3} O^{+}$

(Conjugate acid-base pair differ only by a proton)

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Equilibrium - Result Question 54

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