Equilibrium - Result Question 54

####56. Conjugate acid of $NH_2^{-}$is :

(a) $NH_4^{+}$

(b) $NH_3$

(c) $NH_2$

(d) $NH$

[2000]

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Solution:

  1. (b) Because $NH_3$ after losing a proton $(H^{+})$ gives $NH_2{ }^{-}$

$NH_3+H_2 O \rightarrow NH_2^{-}+H_3 O^{+}$

(Conjugate acid-base pair differ only by a proton)



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