Equilibrium - Result Question 54
####56. Conjugate acid of $NH_2^{-}$is :
(a) $NH_4^{+}$
(b) $NH_3$
(c) $NH_2$
(d) $NH$
[2000]
Show Answer
Solution:
- (b) Because $NH_3$ after losing a proton $(H^{+})$ gives $NH_2{ }^{-}$
$NH_3+H_2 O \rightarrow NH_2^{-}+H_3 O^{+}$
(Conjugate acid-base pair differ only by a proton)