Equilibrium - Result Question 52
####54. In $HS^{-}, I^{-}, RNH_2$ and $NH_3$, order of proton accepting tendency will be
(a) $I^{-}>NH_3>RNH_2>HS^{-}$
[2001]
(b) $HS^{-}>RNH_2>NH_3>I^{-}$
(c) $RNH_2>NH_3>HS^{-}>I^{-}$
(d) $NH_3>RNH_2>HS^{-}>I^{-}$
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Solution:
- (c) Strong base has higher tendency to accept the proton. Increasing order of base and hence the order of accepting tendency of proton is
$ I^{-}<HS^{-}<NH_3<RNH_2 $
