Equilibrium - Result Question 48
####50. What is the correct relationship between the $pHs$ of isomolar solutions of sodium oxide $(pH_1)$, sodium sulphide $(pH_2)$, sodium selenide $(pH_3)$ and sodium telluride $(pH_4)$ ?
[2005]
(a) $pH_1>pH_2>pH_3>pH_4$
(b) $pH_1>pH_2 \approx pH_3>pH_4$
(c) $pH_1<pH_2<pH_3<pH_4$
(d) $pH_1<pH_2<pH_3 \approx pH_4$
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Solution:
- (a) The solution formed from isomolar solutions of sodium oxide, sodium sulphide, sodium selenide and sodium telluride are $H_2 O$, $H_2 S, H_2 Se & H_2$ Te respectively. As the acidic strengh increases from $H_2 O$ to $H_2$ Te thus $pH$ decreases and hence the correct order of $pHs$ is $pH_1>pH_2>pH_3>pH_4$.
