Equilibrium - Result Question 4
####4. If the equilibrium constant for
$N_2(g)+O_2(g) \rightarrow 2 NO(g)$ is $K$, the equilibrium constant for
[2015 RS] $\frac{1}{2} N_2(g)+\frac{1}{2} O_2(g) \rightarrow NO(g)$ will be:
(a)
(b) $\frac{1}{2} K$
(c) $K$
(d) $K^{2}$
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Solution:
- (a) $N_2(g)+O_2(g) \rightarrow 2 NO(g)$
$K=\frac{[NO]^{2}}{[N_2][O_2]}$
$ \begin{aligned} & \frac{1}{2} N_2+\frac{1}{2} O_2 \rightarrow NO \\ & K^{\prime}=\frac{[NO]}{[N_2]^{1 / 2}[O_2]^{1 / 2}}=K^{1 / 2} \end{aligned} $
5 .
$ \text{ (c) } 2 SO_2+O_2 \rightarrow 2 SO_3 K=278 \text{ (given) } $
$SO_3 \rightarrow SO_2+\frac{1}{2} O_2 \quad K^{\prime}=(\sqrt{\frac{1}{K}})$
$=\sqrt{\frac{1}{278}}=6 \times 10^{-2}$
