SATHEE: Equilibrium - Result Question 38

Equilibrium - Result Question 38

####40. What is the $p H$ of the resulting solution when equal volumes of $0.1 M N a O H$ and $0.01 M H C l$ are mixed?

(a) 12.65

(b) 2.0

(d) 1.04

[2015 RS]

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Solution:

(a) g eq of $N a O H = 0.1 \times V = 0.1 V$

$g$ eq of $H C l = 0.01 \times V = 0.01 V$

$g$ eq of $N a O H > g$ eq. $H C l$

hence, resultant solution should be basic, hence from the eqn

$M_{1} V_{1} - M_{2} V_{2} = M V$

$0.1 V - 0.01 V = M V$

$M = \frac{0.09}{2} = 0.045 = 4.5 \times 10^{- 2}$

Now, $p O H = - \log [O H^{-}]$

$= - \log 4.5 \times 10^{- 2} = 1.34$

$∵ p H + p O H = 14$

$∴ p H = 14 - 1.34 = 12.65$

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Equilibrium - Result Question 38

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