SATHEE: Equilibrium - Result Question 34

Equilibrium - Result Question 34

####36. The $p H$ of $0.01 M N a O H$ (aq) solution will be [NEET Odisha 2019]

(a) 9

(b) 7.01

(d) 12

Show Answer

Solution:

(d) $[O H^{-}] = 0.01 M = 10^{- 2} M$

$\begin{aligned} pOH = - \log [O H^{-}] = - \log (10^{- 2}) = 2 \\ pH = 14 - pOH = 12 \end{aligned}$

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Equilibrium - Result Question 34

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