Equilibrium - Result Question 29

####30. For the reaction

2BaO2(s)2BaO(s)+O2(g);

ΔH=+ve. In equilibrium condition, pressure of

O2 is dependent on

[2002]

(a) mass of BaO2

(b) mass of BaO

(c) temperature of equilibrium

(d) mass of BaO2 and BaO both

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Solution:

  1. (c) For the reaction BaO2(s)BaO(s)+O2(g);ΔH=+ve.

At equilibrium Kp=PO2

[For solid and liquids concentration term is taken as unity]

Hence, the value of equilibrium constant depends only upon partial pressure of O2. Further on increasing temperature, formation of O2 increases as this is an endothermic reaction.

since the steps 1 and 2 are exothermic hence low temprature will favour both the reactions. In step -1 , moles are increasing hence low pressure will favour it. In step 2, moles are decreasing, hence high pressure will favour it.



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