SATHEE: Equilibrium - Result Question 2

Equilibrium - Result Question 2

####2. A 20 litre container at $400 K$ contains $C O_{2} (g)$ at pressure $0.4 a t m$ and an excess of $S r O$ (neglect the volume of solid $S r O$ ). The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of $C O_{2}$ attains its maximum value, will be :

(Given that: $S r C O_{3} (s) \to S r O (s) + C O_{2} (g), K p$ $= 1.6 a t m$ )

(a) 10 litre

(b) 4 litre

(d) 5 litre

[2017]

Show Answer

Solution:

(d) Max. pressure of $C O_{2} =$ Pressure of $C O_{2}$ at equilibrium

For reaction,

$S r C O_{3} (s) \to S r O (s) + C O_{2} (g)$ $K_{p} = P_{C O_{2}} = 1.6 a t m =$ maximum pressure of $C O_{2}$ volume of container at this stage.

$V = \frac{n R T}{P}$

Since container is sealed and reaction was not earlier at equilibrium.

$∴ n =$ constant.

$n = \frac{P V}{R T} = \frac{0.4 \times 20}{R T}$

Put equation (ii) in equation (i)

$V = [\frac{0.4 \times 20}{R T}] \frac{R T}{1.6} = 5 L$

Equilibrium - Result Question 2

Solution:

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Equilibrium - Result Question 2

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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