SATHEE: Equilibrium - Result Question 19

Equilibrium - Result Question 19

####20. If $α$ is the fraction of $H I$ dissociated at equilibrium in the reaction, $2 H I (g) \to H_{2}$ $(g) + I_{2} (g)$ , starting with 2 moles of $H I$ , the total number of moles of reactants and products at equilibrium are

[1996]

(a) $2 + 2 α$

(b) 2

(c) $1 + α$

(d) $2 - α$

Show Answer

Solution:

(b) According to equation

Total moles at equilibrium $= 2 - 2 α + α + α = 2$ mole

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