SATHEE: Equilibrium - Result Question 1

Equilibrium - Result Question 1

####1. The equilibrium constant of the following are :

$\begin{matrix} N_{2} + 3 H_{2} \to 2 N H_{3} & K_{1} \\ N_{2} + O_{2} \to 2 N O & K_{2} \\ H_{2} + \frac{1}{2} O_{2} \to H_{2} O & K_{3} \end{matrix}$

The equilibrium constant $(K)$ of the reaction :

$2 N H_{3} + \frac{5}{2} O_{2} \overset{K}{\to} 2 N O + 3 H_{2} O$ , will be;

(a) $K_{2} K_{3}^{3} / K_{1}$

(b) $K_{2} K_{3} / K_{1}$

(d) $K_{1} K_{3}^{3} / K_{2}$

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Solution:

(i) $N_{2} + 3 H_{2} \to 2 N H_{3}; K_{1} = \frac{[N H_{3}]^{2}}{[N_{2}] [H_{2}]^{3}}$

(ii) $N_{2} + O_{2} \to 2 N O; K_{2} = \frac{[N O]^{2}}{[N_{2}] [O_{2}]}$

(iii) $H_{2} + \frac{1}{2} O_{2} ⟶ H_{2} O; K_{3} = \frac{[H_{2} O]}{[H_{2}] [O_{2}]^{1 / 2}}$

Applying (II $+ 3 \times I I I - I)$ we will get

$2 N H_{3} + \frac{5}{2} O_{2} \overset{K}{\to} 2 N O + 3 H_{2} O$ ;

$K = \frac{[N O]^{2}}{[N_{2}] [O_{2}]} \times \frac{[H_{2} O]^{3}}{[H_{2}]^{3} \times [O_{2}]^{3 / 2}} / \frac{[N H_{3}]^{2}}{[N_{2}] [H_{2}]^{3}}$

$∴ K = K_{2} \times K_{3}^{3} / K_{1}$

Equilibrium - Result Question 1

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Equilibrium - Result Question 1

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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