Electrochemistry - Result Question 58
####60. A button cell used in watches functions as following
$ \begin{aligned} & Zn(s)+Ag_2 O(s)+ H_2 O(l) \rightarrow \\ & 2 Ag(s)+Zn^{2+}(aq)+2 OH^{-}(aq) \end{aligned} $
If half cell potentials are :
$Zn^{2+}(aq)+2 e^{-} \to Zn(s) ; E^{0}=-0.76 V$
$Ag_2 O(s)+H_2 O(l)+2 e^{-} \to 2 Ag(s)+$
$2 OH^{-}(aq) ; E^{o}=0.34 V$ The cell potential will be :
(a) $0.42 V$
(b) $0.84 V$
(c) $1.34 V$
(d) $1.10 V$
[NEET 2013]
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Solution:
- (d) $E _{\text{Cell }}^{\circ}=E^{\circ} _{O P}+E^{\circ} _{R P}=0.76+0.34=1.10 V$
