SATHEE: Electrochemistry - Result Question 5

Electrochemistry - Result Question 5

####6. Molar conductivities $(Λ_{m}^{\circ})$ at infinite dilution of $N a C l, H C l$ and $C H_{3} C O O N a$ are 126.4, 425.9 and $91.0 S c m^{2} m o l^{- 1}$ respectively. $Λ_{m}^{\circ}$ for $C H_{3} C O O H$ will be :

[2012 M]

(a) $425.5 S c m^{2} m o l^{- 1}$

(b) $180.5 S c m^{2} m o l^{- 1}$

(d) $390.5 S c m^{2} m o l^{- 1}$

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Solution:

$(d) \begin{aligned} Λ_{C H_{3} C O O H}^{o} & = Λ_{C H_{3} C O O N a}^{o} + Λ_{H} C l^{o} - Λ_{N} a C l^{o} \\ = 91 + 425.9 - 126.4 = 390.5 \end{aligned}$

Electrochemistry - Result Question 5

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Electrochemistry - Result Question 5

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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