Electrochemistry - Result Question 5
####6. Molar conductivities $(\Lambda_m^{\circ})$ at infinite dilution of $NaCl, HCl$ and $CH_3 COONa$ are 126.4, 425.9 and $91.0 S cm^{2} mol^{-1}$ respectively. $\Lambda_m^{\circ}$ for $CH_3 COOH$ will be :
[2012 M]
(a) $425.5 S cm^{2} mol^{-1}$
(b) $180.5 S cm^{2} mol^{-1}$
(c) $290.8 S cm^{2} mol^{-1}$
(d) $390.5 S cm^{2} mol^{-1}$
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Solution:
$ \text{ (d) } \begin{aligned} \Lambda _{CH_3 COOH}^{o} & =\Lambda _{CH_3 COONa}^{o}+\Lambda_HCl^{o}-\Lambda_NaCl^{o} \\ & =91+425.9-126.4=390.5 \end{aligned} $
