SATHEE: Electrochemistry - Result Question 46

Electrochemistry - Result Question 46

####48. The standard e.m.f. of a galvanic cell involving cell reaction with $n = 2$ is found to be $0.295 V$ at $25^{\circ} C$ . The equilibrium constant of the reaction would be

(Given $F = 96500 C m o l^{- 1}; R = 8.314 J K^{- 1} m o l^{- 1}$ )

(a) $2.0 \times 10^{11}$

(b) $4.0 \times 10^{12}$

(d) $1.0 \times 10^{10}$

[2004]

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Solution:

(d) $E^{\circ} = \frac{0.0591}{n} \log_{10} K$

Here, $n = 2, E^{\circ} = 0.295$

$∴ \log_{10} K = \frac{2 \times 0.295}{0.0591} = 10$ or $K = 1 \times 10^{10}$

Electrochemistry - Result Question 46

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Electrochemistry - Result Question 46

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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