Electrochemistry - Result Question 42

####44. On the basis of the following E∘ values, the strongest oxidizing agent is :

[2008]

[Fe(CN)6]4−→[Fe(CN)6]3−+e−;E∘=−0.35V

Fe2+→Fe3++e−E∘=−0.77V

(a) [Fe(CN)6]4

(b) Fe2+

(c) Fe3+

(d) [Fe(CN)6]3−

Show Answer

Solution:

  1. (c) From the given data we find Fe3+ (E(Fe3+/Fe2+)∘=+0.77V) is strongest oxidizing agent.

More the positive value of reduction potential, more is the tendency to get reduced (better oxidising agent).

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