Electrochemistry - Result Question 40

####42. Consider the following relations for emf of a electrochemical cell:

[2010]

(i) emf of cell =( Oxidation potential of anode ) - (Reduction potential of cathode)

(ii) emf of cell =( Oxidation potential of anode ) + (Reduction potential of cathode)

(iii) emf of cell =( Reduction potential of anode ) + (Reduction potential of cathode)

(iv) emf of cell =( Oxidation potential of anode ) -(Oxidation potential of cathode)

Which of the above relations are correct?

(a) (ii) and (iv)

(b) (iii) and (i)

(c) (i) and (ii)

(d) (iii) and (iv)

Show Answer

Solution:

(a) Ecell =Ecathode Eanode 

Ecell =Ered / cathode +Eoxi/anode 

Ecell =Eoxi / cathode +Eoxi/anode 

Hence, option (a) is correct.



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