SATHEE: Electrochemistry - Result Question 38

Electrochemistry - Result Question 38

####40. A solution contains $F e^{2 +}, F e^{3 +}$ and $I^{-}$ ions. This solution was treated with iodine at $35^{\circ} C$ . $E^{\circ}$ for $F e^{3 +} / F e^{2 +}$ is $+ 0.77 V$ and $E^{\circ}$ for $I_{2} / 2 I^{-} = 0.536 V$ . The favourable redox reaction is : [2011 M]

(a) $I_{2}$ will be reduced to $I^{-}$

(b) There will be no redox reaction

(d) $F e^{2 +}$ will be oxidised to $F e^{3 +}$

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Solution:

and $I_{2} / 2 I^{-} = 0.536 V$

Reduction potential of $F e^{3 +} / F e^{2 +} > I_{2} / I^{-}$ , so $F e^{3 +}$ will be reduced and $I^{-}$ will be oxidised.

Electrochemistry - Result Question 38

Solution:

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Electrochemistry - Result Question 38

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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