SATHEE: Electrochemistry - Result Question 27

Electrochemistry - Result Question 27

####29. For a cell involving one electron $E_{cell}^{!} = 0.59 V$ at $298 K$ , the equilibrium constant for the cell reaction is :

[2019]

$[.$ Given that $\frac{2.303 R T}{F} = 0.059 V$ at $. T = 298 K]$

(a) $1.0 \times 10^{2}$

(b) $1.0 \times 10^{5}$

(d) $1.0 \times 10^{30}$

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Solution:

Given : $E_{cell}^{\circ} = 0.59 V, n = 1$

$0.59 = \frac{0.059}{1} \log K$

$\frac{0.59}{0.059} = \log K$

$10 = \log k$

$K = 10^{10}$

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Electrochemistry - Result Question 27

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