Electrochemistry - Result Question 21
####22. How many grams of cobalt metal will be deposited when a solution of cobalt (II) chloride is electrolyzed with a current of 10 amperes for 109 minutes $(1$ Faraday $=96,500 C$; Atomic mass of $Co=59 u)$
[NEET Kar: 2013]
(a) 0.66
(b) 4.0
(c) 20.0
(d) 40.0
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Solution:
- (c) Applying,
$w=$ Zit $=\frac{\text{ Eit }}{96500}$
Equivalent weight of cobalt (II) $=59 / 2$
$I=10 A$
Time $(t)=109 min=109 \times 60 sec$
Substituting these values we get,
$ w=\frac{59 \times 10 \times 109 \times 60}{2 \times 96500}=20.0 $
