SATHEE: Electrochemistry - Result Question 21

Electrochemistry - Result Question 21

####22. How many grams of cobalt metal will be deposited when a solution of cobalt (II) chloride is electrolyzed with a current of 10 amperes for 109 minutes $(1$ Faraday $= 96, 500 C$ ; Atomic mass of $C o = 59 u)$

[NEET Kar: 2013]

(a) 0.66

(b) 4.0

(d) 40.0

Show Answer

Solution:

$w =$ Zit $= \frac{Eit}{96500}$

Equivalent weight of cobalt (II) $= 59 / 2$

$I = 10 A$

Time $(t) = 109 m i n = 109 \times 60 s e c$

Substituting these values we get,

$w = \frac{59 \times 10 \times 109 \times 60}{2 \times 96500} = 20.0$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Electrochemistry - Result Question 21

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu