SATHEE: Coordination Compounds - Result Question 63

Coordination Compounds - Result Question 63

####70. Considering $H_{2} O$ as a weak field ligand, the number of unpaired electrons in $[M n (H_{2} O)_{6}]^{2 +}$ will be (At. no. of $M n = 25$ )

[2004]

(a) three

(b) five

(d) four

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Solution:

(b) Since $H_{2} O$ is a weak ligand, it will not cause pairing of electrons in the metal ion $M n^{2 +}$ . Thus electronic configuration of the metal $(M n^{2 +})$ in the complex will be

$M n^{2 +} : 1 s^{2} 2 s^{2} p^{6} 3 s^{2} 3 p^{6} 3 d^{5}$

i.e. 5 unpaired electrons.

Coordination Compounds - Result Question 63

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Coordination Compounds - Result Question 63

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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