SATHEE: Coordination Compounds - Result Question 59

Coordination Compounds - Result Question 59

####66. $[C r (H_{2} O)_{6}] C l_{3} ($ at no. of $C r = 24)$ has a magnetic moment of $3.83 B$ . M. The correct distribution of $3 d$ electrons in the chromium of the complex is

(a) $3 d_{x y}^{1}, (3 d_{x^{2} - y^{2}})^{1}, 3 d_{y z}^{1}$

[2006]

(b) $3 d_{x y}^{1}, 3 d_{y z}^{1}, 3 d_{x z}^{1}$

(d) $(3 d_{x}^{2} - y^{2})^{1}, 3 d_{z}^{2}, 3 d_{x z}^{1}$

Show Answer

Solution:

(b) $μ = \sqrt{n (n + 2)}$

$3.83 = \sqrt{n (n + 2)}$

on solving $n = 3$

As per magnetic moment, it has three unpaired electron.

$C r^{3 +}$ will have configuration as $=$

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{3}$

So $3 d_{x y}^{1} 3 d_{y z}^{1} 3 d_{x z}^{1}$

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Coordination Compounds - Result Question 59

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