SATHEE: Coordination Compounds - Result Question 52

Coordination Compounds - Result Question 52

####59. Which of the following complex compounds will exhibit highest paramagnetic behaviour?

[2011M]

(At. No. : $T i = 22, C r = 24, C o = 27, Z n = 30$ )

(a) $[T i (N H_{3})_{6}]^{3 +}$

(b) $[C r (N H_{3})_{6}]^{3 +}$

(c) $[C o (N H_{3})_{6}]^{3 +}$

(d) $[Z n (N H_{3})_{6}]^{2 +}$

Show Answer

Solution:

(b)

(a) $[T i (N H_{3})_{6}]^{3 +} : 3 d^{1}$ configuration and thus has one unpaired electron.

(b) $[C r (N H_{3})_{6}]^{3 +}$ : In this complex $C r$ is in +3 oxidation state.

$C r^{3 +} : 3 d^{3} 4 s^{0}$

Thus, the complex is paramagnetic.

(c) $[C o (N H_{3})_{6}]^{3 +}$ : In this complex, cobalt ion is in +3 oxidation state with $3 d^{6}$ configuration.

$C o^{3 +}, [A r] 3 d^{6}$

$[C o (N H_{3})_{6}]^{3 +}$

(inner orbital or $d^{2} s p^{3}$ hybrid orbital low spin complex) diamagnetic

(d) In this complex Zn exists as

$Z n^{2 +}$ ion

$Z n^{2 +}$ ion : $3 d^{10} 4 s^{0}$

$Z n^{2 +}$ ion in $[Z n (N H_{3})_{4}]^{2 +}$

Due to presence of paired electrons, complex is diamagnetic in nature.

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