SATHEE: Coordination Compounds - Result Question 44

Coordination Compounds - Result Question 44

####47. Which of these statements about $[C o (C N)_{6}]^{3 -}$ is true?

[2015]

(a) $[C o (C N)_{6}]^{3 -}$ has four unpaired electrons and will be in a low-spin configuration.

(b) $[C o (C N)_{6}]^{3 -}$ has four unpaired electrons and will be in a high spin configuration. (c) $[C o (C N)_{6}]^{3 -}$ has no unpaired electrons and will be in a high-spin configuration.

(d) $[C o (C N)_{6}]^{3 -}$ has no unpaired electrons and will be in a low-spin configuration.

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Solution:

(d) $I n [C o (C N)_{6}]^{- 3}$ , O.N. of Co is +3

$∴ C o^{+ 3} = 3 d^{6} 4 s^{0}$

$C N^{-}$ is a strong field ligand

$∴$ Pairing of electrons occurs so in this complex no unpaired electron is present and it is low spin complex.

48 .

(b) Due to $d^{5}$ configuration CFSE is zero.

(b) cis-platin

(d) $[C u (N H_{3})_{4}]^{2 +}$ hybridisation $d s p^{2}$

$C u^{+ 2} - 3 d^{9}$ has one unpaired $e^{-}$

So, magnetic moment

$\begin{aligned} μ & = \sqrt{n (n + 2)} = \sqrt{1 (1 + 2)} \\ = \sqrt{3} = 1.73 \end{aligned}$

Coordination Compounds - Result Question 44

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Coordination Compounds - Result Question 44

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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