SATHEE: Coordination Compounds - Result Question 43

Coordination Compounds - Result Question 43

####46. Pick out the correct statement with respect to $[M n (C N)_{6}]^{3 -}$

[2017]

(a) It is $s p^{3} d^{2}$ hybridised and tetrahedral

(b) It is $d^{2} s p^{3}$ hybridised and octahedral

(d) It is $s p^{3} d^{2}$ hybridised and octahedral

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Solution:

(b) In the complex $[M n (C N)_{6}]^{3 -}$ , O.S. of $M n$ is +3 E.C. of $M n^{+ 3} \to 3 d^{4}$

The presence of a strong field ligand $C N^{-}$ causes pairing of electrons.

As, coordination number of $M n = 6$ , so it will form an octahedral complex.

$∴ [M n (C N)_{6}]^{3 -} =$

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Coordination Compounds - Result Question 43

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