Coordination Compounds - Result Question 38
####40. The Crystal Field Stabilisation Energy (CFSE) for $[CoCl_6]^{4-}$ is $18000 cm^{-1}$. The CFSE for $[CoCl_4]^{2-}$ will be
[NEET Odisha 2019]
(a) $8000 cm^{-1}$
(c) $6000 cm^{-1}$
(c) $16000 cm^{-1}$
(d) $18000 cm^{-1}$
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Solution:
- (a) $\because \Delta_t=\frac{4}{9} \Delta_0$
$\Delta_t=\frac{4}{9} \times 18000 cm^{-1}=8000 cm^{-1}$
