Coordination Compounds - Result Question 28
####30. A coordination complex compound of cobalt has the molecular formula containing five ammonia molecules, one nitro group and two chlorine atoms for one cobalt atom. One mole of this compound produces three mole ions in an aqueous solution. On reacting this solution with excess of $AgNO_3$ solution, we get two moles of $AgCl$ precipitate. The ionic formula for this complex would be
[1998]
(a) $[Co(NH_3)_4(NO_2) Cl][(NH_3) Cl]$
(b) $[Co(NH_3)_5 Cl][Cl(NO_2)]$
(c) $[Co(NH_3)_5(NO_2)] Cl_2$
(d) $[Co(NH_3)_5][(NO_2)_2 Cl_2]$
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Solution:
- (c) As it forms two moles of silver chloride thus it has two moles of ionisable $Cl$.
$[Co(NH_3)_5 NO_2] Cl_2 \to[Co(NH_3)_5 NO_2]^{2+}+2 Cl^{-}$ $2 Cl^{-}+2 AgNO_3 \to 2 AgCl+2 NO_3^{-}$
