Classification of Elements and Periodicity in Properties - Result Question 3
####3. The element $Z=114$ has been discovered recently. It will belong to which of the following family/ group and electronic configuration? [2017]
(a) Carbon family, $[Rn] 5 f^{14} 6 d^{10} 7 s^{2} 7 p^{2}$
(b) Oxygen family, $[Rn] 5 f^{14} 6 d^{10} 7 s^{2} 7 p^{4}$
(c) Nitrogen family, $[Rn] 5 f^{14} 6 d^{10} 7 s^{2} 7 p^{6}$
(d) Halogen family, $[Rn] 5 f^{14} 6 d^{10} 7 s^{2} 7 p^{5}$
Show Answer
Solution:
- (a) After $ _{86} Rn$ (Group 18), elements from atomic number 89 to 103 (actinides) are in group 3 $114=103+11$. Thus, element with atomic number 114 will be in group $(3+11)$ or group 14 (carbon family).
The outer shell configuration of group 14 is $n s^{2}=n p^{2}$.
Hence, only option (a) is correct.
