Chemical Kinetics - Result Question 57
####58. Activation energy of a chemical reaction can be determined by
[1998]
(a) evaluating rate constant at standard temperature
(b) evaluating velocities of reaction at two different temperatures
(c) evaluating rate constants at two different temperatures
(d) changing concentration of reactants
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Solution:
- (c) We know that the activation energy of chemical reaction is given by formula $=$ $\log \frac{k_2}{k_1}=\frac{E_a}{2.303 R} \frac{e_2^{e} T_2-T_1}{\stackrel{e}{e} T_1 T_2} \underset{u}{u}$, where $k_1$ is the rate constant at temperature $T_1$ and $k_2$ is the rate constant at temperature $T_2$ and $E_a$ is the activation energy. Therefore, activation energy of chemical reaction is determined by evaluating rate constant at two different temperatures.
