SATHEE: Chemical Kinetics - Result Question 54

Chemical Kinetics - Result Question 54

####55. The temperature dependence of rate constant $(k)$ of a chemical reaction is written in terms of Arrhenius equation, $k=A e^{-E_a^{} / R T} $. A c t i v a t i o n e n e r g y$ (E_a^{})$ of the reaction can be calculated by plotting

[2003]

(a) $\log k$ vs $\frac{1}{\log T}$

(b) $k$ vs $T$

(d) $\log k v s \frac{1}{T}$

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Solution:

(d) $k = A e^{- E_{a} / R T}$

or $\log T = \log A - \frac{E_{a}}{2.303 R T}$

Comparing the above equation with $y = m x + c$

$y = \log k, x = \frac{1}{T}$

Thus a plot of $\log_{10} k v s 1 / T$ should be a straight line, with slope equal to $- E_{a} / 2.303 R$ and intercept equal to $\log A$

or $E_{a} = - 2.303 R \times$ Slope

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Chemical Kinetics - Result Question 54

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