SATHEE: Chemical Kinetics - Result Question 5

Chemical Kinetics - Result Question 5

####5. The rate constant of the reaction $A \to B$ is $0.6 \times 10^{- 3}$ mole per second. If the concentration of $A$ is $5 M$ then concentration of $B$ after 20 minutes is :

[2015 RS]

(a) $1.08 M$

(b) $3.60 M$

(d) $0.72 M$

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Solution:

(d) Rate constant $k = 0.6 \times 10^{- 3}$ mole per second. (unit mole per second shows zero order reaction) For a zero order reaction

$\begin{aligned} [A] = [A]_{0} - k t \\ and [A_{0}] - [A] = [B] = k t \\ = 0.6 \times 10^{- 3} \times 20 \times 60 = 0.72 M \end{aligned}$

Chemical Kinetics - Result Question 5

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Chemical Kinetics - Result Question 5

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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