SATHEE: Chemical Kinetics - Result Question 42

Chemical Kinetics - Result Question 42

####42. Half life of a first order reaction is $4 s$ and the initial concentration of the reactants is $0.12 M$ . The concentration of the reactant left after $16 s$ is

(a) $0.0075 M$

(b) $0.06 M$

(d) $0.015 M$

[1999]

Show Answer

Solution:

$\begin{matrix} (a) t_{1 / 2} = 4 s & T = 16 \\ n = \frac{T}{t_{1 / 2}} = \frac{16}{4} = 4 \\ A = A_{o} (\frac{1}{2})^{n} = 0.12 \times (\frac{1}{2})^{4} = \frac{0.12}{16} = 0.0075 M \end{matrix}$

where $A_{o} =$ initial concentration &

$A =$ concentration left after time $t$ .

Chemical Kinetics - Result Question 42

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Chemical Kinetics - Result Question 42

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu