SATHEE: Chemical Kinetics - Result Question 38

Chemical Kinetics - Result Question 38

####38. The rate of a first order reaction is $1.5 \times 10^{- 2}$ $m o l L^{- 1} m i n^{- 1}$ at $0.5 M$ concentration of the reactant. The half life of the reaction is [2004]

(a) $0.383 m i n$

(b) $23.1 m i n$

(d) $7.53 m i n$

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Solution:

(b) For a first order reaction, $A \to$ products

$r = k [A]$ or $k = \frac{r}{[A]}$

$\Rightarrow k = \frac{1.5 \times 10^{- 2}}{0.5} = 3 \times 10^{- 2}$

Further, $t_{1 / 2} = \frac{0.693}{k} = \frac{0.693}{3 \times 10^{- 2}} = 23.1 m i n$ .

Chemical Kinetics - Result Question 38

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Chemical Kinetics - Result Question 38

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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