SATHEE: Chemical Kinetics - Result Question 35

Chemical Kinetics - Result Question 35

####35. If $60$ of a first order reaction was completed in 60 minutes, $50$ of the same reaction would be completed in aproximately

(a) 45 minutes

(b) 60 minutes

(d) 50 minutes

[2007] $(\log 4 = 0.60, \log 5 = 0.69)$

Show Answer

Solution:

(a) For a first order reaction

$k = \frac{2.303}{t} \log \frac{a}{a - x}$

when $t = 60$ and $x = 60$

$k = \frac{2.303}{60} \log \frac{100}{100 - 60} = \frac{2.303}{60} \log \frac{100}{40} = 0.0153$ Now,

$\begin{aligned} t_{1 / 2} & = \frac{2.303}{0.0153} \log \frac{100}{100 - 50} = \frac{2.303}{0.0153} \times \log 2 \\ = \frac{2.303}{0.0153} \times 0.3010 = 45.31 m i n . \end{aligned}$

Chemical Kinetics - Result Question 35

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Chemical Kinetics - Result Question 35

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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