SATHEE: Chemical Kinetics - Result Question 3

Chemical Kinetics - Result Question 3

####3. For the chemical reaction

$N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g)$

the correct option is:

[2019] (a) $- \frac{1}{3} \frac{d [H_{2}]}{d t} = - \frac{1}{2} \frac{d [N H_{3}]}{d t}$

(b) $- \frac{d [N_{2}]}{d t} = 2 \frac{d [N H_{3}]}{d t}$

(c) $- \frac{d [N_{2}]}{d t} = \frac{1}{2} \frac{d [N H_{3}]}{d t}$

(d) $3 \frac{d [H_{2}]}{d t} = 2 \frac{d [N H_{3}]}{d t}$

Show Answer

Solution:

$\begin{aligned} (c) N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g) \\ \frac{- d [N_{2}]}{d t} = \frac{- 1}{3} \frac{d [H_{2}]}{d t} = \frac{1}{2} \frac{d [N H_{3}]}{d t} \end{aligned}$

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