Chemical Kinetics - Result Question 3
####3. For the chemical reaction
$N_2(g)+3 H_2(g) \rightarrow 2 NH_3(g)$
the correct option is:
[2019] (a) $-\frac{1}{3} \frac{d[H_2]}{d t}=-\frac{1}{2} \frac{d[NH_3]}{d t}$
(b) $-\frac{d[N_2]}{d t}=2 \frac{d[NH_3]}{d t}$
(c) $-\frac{d[N_2]}{d t}=\frac{1}{2} \frac{d[NH_3]}{d t}$
(d) $3 \frac{d[H_2]}{d t}=2 \frac{d[NH_3]}{d t}$
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Solution:
$ \begin{aligned} & \text{ (c) } N_2(g)+3 H_2(g) \rightarrow 2 NH_3(g) \\ & \frac{-d[N_2]}{dt}=\frac{-1}{3} \frac{d[H_2]}{dt}=\frac{1}{2} \frac{d[NH_3]}{dt} \end{aligned} $
