Chemical Kinetics - Result Question 26
####26. In a zero-order reaction for every $10^{\circ}$ rise of temperature, the rate is doubled. If the temperature is increased from $10^{\circ} C$ to $100^{\circ} C$, the rate of the reaction will become :
[2012]
(a) 256 times
(b) 512 times
(c) 64 times
(d) 128 times
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Solution:
- (b) $\frac{r _{100^{\circ} C}}{r _{10}{ }^{\circ} C}=2^{(\frac{100-10}{10})}=2^{9}=512$ times
