SATHEE: Chemical Kinetics - Result Question 2

Chemical Kinetics - Result Question 2

####2. If the rate constant for a first order reaction is $k$ , the time $(t)$ required for the completion of $99$ of the reaction is given by:

[2019]

(a) $t = 0.693 / k$

(b) $t = 6.909 / k$

(d) $t = 2.303 / k$

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Solution:

$t = \frac{2.303}{k} \log \frac{[A]_{o}}{[A]}$

for $99$ completion of the reaction,

$\begin{aligned} t = \frac{2.303}{k} \log \frac{100}{100 - 99} \\ t = \frac{2.303}{k} \log 10^{2} \\ t = \frac{4.606}{k} \end{aligned}$

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Chemical Kinetics - Result Question 2

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