Chemical Kinetics - Result Question 14
####14. $3 A \to 2 B$, rate of reaction $\frac{d[B]}{d t}$ is equal to
(a) $-\frac{3}{2} \frac{d[A]}{d t}$
(b) $-\frac{2}{3} \frac{d[A]}{d t}$
(c) $-\frac{1}{3} \frac{d[A]}{d t}$
(d) $+2 \frac{d[A]}{d t}$
[2002]
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Solution:
- (b) $3 A \longrightarrow 2 B$
Rate of appearance of $B$ is equal to rate of disappearance of $A$.
$\frac{1}{2} \frac{d[B]}{d t}=-\frac{1}{3} \frac{d[A]}{d t} \Rightarrow \frac{d[B]}{d t}=-\frac{2}{3} \frac{d[A]}{d t}$
