Chemical Bonding and Molecular Structure - Result Question 95
####97. Which of the following options represents the correct bond order?
[2015]
(a)
(b)
(c)
(d)
Show Answer
Solution:
- (a) Oxygen molecule
$\sigma 1 s^{2}<\sigma^{} 1 s^{2}<\sigma 2 s^{2}<\sigma^{} 2 s^{2}<\sigma 2 p_x^{2}$
$ <\pi 2 p_y^{2}=\pi 2 p_z^{2}<\pi^{} 2 p_y^{1}=\pi^{} 2 p_z^{1} $
Bond order
Electronic configuration
$ \begin{aligned} \sigma 1 s^{2}<\sigma^{} 1 s^{2}<\sigma 2 s^{2} & <\sigma^{} 2 s^{2}<\sigma 2 p_x^{2} \ <\pi 2 p_y^{2} & =\pi 2 p_z^{2}<\pi^{*} 2 p_y^{1} \end{aligned} $
Bond order
$ \begin{aligned} \sigma 1 s^{2}<\sigma^{} 1 s^{2} & <\sigma 2 s^{2}<\sigma^{} 2 s^{2}<\sigma 2 p_x^{2} \ & <\pi 2 p_y^{2}=\pi 2 p_z^{2}<\pi^{} 2 p_y^{2}=\pi^{} 2 p_z^{1} \end{aligned} $
Bond order
