SATHEE: Chemical Bonding and Molecular Structure

Chemical Bonding and Molecular Structure - Result Question 93

####95. Which of the following pairs of species have the same bond order?

[2017]

(a) $O_{2}, N O^{+}$

(b) $C N^{-}, C O$

(d) $C O, N O$

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Solution:

(b) $C N^{-}$ and $C O$ have same no. of electrons and have same bond order equal to 3 .

Short cut trick to calculate the bond order:

$N_{2}$ has 14 electrons and its bond order is 3 . We have to remember this concept that every electron added or subtracted to 14 , reduces the bond order by 0.5 . For example

$C N^{-} \Rightarrow$ no. of electrons $= 6 + 7 + 1 = 14$

$∴$ bond order $= 3$

$C O \Rightarrow$ no. of electrons $= 6 + 8 = 14$

$∴$ bond order $= 3$

NO $\Rightarrow$ no. of electrons $= 7 + 8 = 15$

$∴$ bond order $= 3 - 0.5 = 2.5$

$N O^{+} \Rightarrow$ no. of electrons $= 7 + 8 - 1 = 14$

$∴$ bond order $= 3$

$O_{2}^{-} \Rightarrow$ no. of electrons $= 8 + 8 + 1 = 17$

$∴$ bond order $= 3 - 1.5$

Please note that this method will work for any species that have electrons between 10 and 18 .

Chemical Bonding and Molecular Structure - Result Question 93

Solution:

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Chemical Bonding and Molecular Structure - Result Question 93

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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