SATHEE: Chemical Bonding and Molecular Structure

Chemical Bonding and Molecular Structure - Result Question 74

####76. The cylindrical shape of an alkyne is due to the fact that it has

(a) three sigma $C - C$ bonds

[1997]

(b) two sigma $C - C$ and one ’ $π$ ’ $C - C$ bond

(c) three ’ $π$ ’ $C - C$ bonds

(d) one sigma $C - C$ and two ’ $π$ ’ $C - C$ bonds

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Solution:

(d) In alkynes the hybridisation is $s p$ i.e each carbon atom undergoes $s p$ hybridisation to form two $s p$ -hybrid orbitals. The two $2 p$ -orbitals remain unhybridised. Hybrid orbitals form one sigma and two unhybridised orbitals form $π$ bonds.

Hence two $π$ bond and one sigma bond between $C - C$ lead to cylindrical shape.

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Chemical Bonding and Molecular Structure - Result Question 74

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