SATHEE: Chemical Bonding and Molecular Structure

Chemical Bonding and Molecular Structure - Result Question 67

####68. Which of the following has $p_{π} - d_{π}$ bonding?

(a) $N O_{3}^{-}$

(b) $S O_{3}^{2 -}$

(d) $C O_{3}^{2 -}$

[2002]

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Solution:

(b) In $S O_{3}^{- 2}$

$O_{σ}^{- π} S \frac{σ}{\overset{σ}{σ} O^{-}} O^{-}$

$S$ is $s p^{3}$ hybridised, so

$_{16} S = 1 s^{2} 2 s^{2} 2 p^{6} \underset{s p^{3} hybridisation}{\underset{⏟}{3 s^{2} 3 p_{x}^{1} 3 p_{y}^{1} 3 p_{z}^{1}}} \underset{unhybride}{\underset{⏟}{3 d_{x y}^{1}}}$

In ‘S’ unhybride $d$ -orbital is present, which will involved in $π$ bond formation with oxygen atom.

$_{8} O = 1 s^{2} 2 s^{2} 2 p_{x}^{2} 2 p_{y}^{1} 2 p_{z}^{1}$

In oxygen two unpaired $p$ -orbital is present in these one is involved in $σ$ bond formation while other is used in $π$ bond formation

Thus in $S O_{3}^{2 -}$ , p $π$ and $d π$ orbitals are involved for $p π - d π$ bonding.

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Chemical Bonding and Molecular Structure - Result Question 67

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