SATHEE: Chemical Bonding and Molecular Structure

Chemical Bonding and Molecular Structure - Result Question 46

####47. Which one of the following species has plane triangular shape?

[2014]

(a) $N_{3}^{-}$

(b) $N O_{3}^{-}$

(d) $C O_{2}$

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Solution:

(b) Hybridization of $N O_{3}^{-} = \frac{1}{2} (5 + 0 + 1 - 0)$ $= \frac{6}{2} = 3 = s p^{2}$ hence geometry is trigonal planner.

$N O_{2}^{-}$ (nitrite ion) also has $s p^{2}$ hybridization and gives a trigonal planner geometry but because there are only two outer atoms, the molecular geometry is bent with $Ð 120^{\circ}$ bond angles.

Chemical Bonding and Molecular Structure - Result Question 46

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Chemical Bonding and Molecular Structure - Result Question 46

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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