SATHEE: Chemical Bonding and Molecular Structure

Chemical Bonding and Molecular Structure - Result Question 33

####34. The dipole moments of diatomic molecules $A B$ and $C D$ are $10.41 D$ and $10.27 D$ , respectively while their bond distances are 2.82 and $2.67 \AA$ , respectively. This indicates that

[1999]

(a) bonding is $100$ ionic in both the molecules

(b) $A B$ has more ionic bond character than $C D$

(d) bonding is nearly covalent in both the molecules

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Solution:

D. M. of $A B$ molecules

$= 4.8 \times 10^{- 10} \times 2.82 \times 10^{- 8} = 13.53 D$

D.M. of $C D$ molecules

$= 4.8 \times 10^{- 10} \times 2.67 \times 10^{- 10} = 12.81 D$

now ionic character

$= \frac{Actual dipole moment of the bond}{Dipole moment of pure ionic compound}$

ionic character in

$A B = \frac{10.41}{13.53} \times 100 = 76.94$

ionic character in

$C D = \frac{10.27}{12.81} \times 100 = 80.23$

Chemical Bonding and Molecular Structure - Result Question 33

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Chemical Bonding and Molecular Structure - Result Question 33

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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