Chemical Bonding and Molecular Structure - Result Question 32
####33. $H_2 O$ is dipolar, whereas $BeF_2$ is not. It is because
[2004]
(a) the electronegativity of $F$ is greater than that of $O$
(b) $H_2 O$ involves hydrogen bonding whereas $BeF_2$ is a discrete molecule
(c) $H_2 O$ is linear and $BeF_2$ is angular
(d) $H_2 O$ is angular and $BeF_2$ is linear
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Solution:
- (d) In a linear symmetrical molecule like $BeF_2$, the bond angle between three atoms is $180^{\circ}$, hence the polarity due to one bond is cancelled by the equal polarity due to other bond. $H_2 O$ is angular.
