SATHEE: Chemical Bonding and Molecular Structure

Chemical Bonding and Molecular Structure - Result Question 32

####33. $H_{2} O$ is dipolar, whereas $B e F_{2}$ is not. It is because

[2004]

(a) the electronegativity of $F$ is greater than that of $O$

(b) $H_{2} O$ involves hydrogen bonding whereas $B e F_{2}$ is a discrete molecule

(d) $H_{2} O$ is angular and $B e F_{2}$ is linear

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Solution:

(d) In a linear symmetrical molecule like $B e F_{2}$ , the bond angle between three atoms is $180^{\circ}$ , hence the polarity due to one bond is cancelled by the equal polarity due to other bond. $H_{2} O$ is angular.

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Chemical Bonding and Molecular Structure - Result Question 32

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