Chemical Bonding and Molecular Structure - Result Question 31
####32. The correct order of the $O-O$ bond length in $O_2$, $H_2 O_2$ and $O_3$ is
[1995, 2005]
(a) $O_2>O_3>H_2 O_2$
(b) $O_3>H_2 O_2>O_2$
(c) $O_2>H_2 O_2>O_3$
(d) $H_2 O_2>O_3>O_2$
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Solution:
- (d) In $H-O-O-H$, the $O-O$ bond is purely single. $O_3$ molecule is a resonance hybrid of two structures : $O=O \to O$ and $O \to O$ $=O$. Thus, its bond length will be longer than $O_2$ molecule which has purely double bond $(O=O)$. Hence, the correct order is:
$H_2 O_2>O_3>O_2$ (bond length of $O-O$ )
