SATHEE: Chemical Bonding and Molecular Structure

Chemical Bonding and Molecular Structure - Result Question 29

####30. The electronegativity difference between $N$ and $F$ is greater than that between $N$ and $H$ yet the dipole moment of $N H_{3} (1.5 D)$ is larger than that of $N F_{3} (0.2 D)$ . This is because

[2006]

(a) in $N H_{3}$ the atomic dipole and bond dipole are in the same direction whereas in $N F_{3}$ these are in opposite directions

(b) in $N H_{3}$ as well as $N F_{3}$ the atomic dipole and bond dipole are in opposite directions

(c) in $N H_{3}$ the atomic dipole and bond dipole are in the opposite directions whereas in $N F_{3}$ these are in the same direction

(d) in $N H_{3}$ as well as in $N F_{3}$ the atomic dipole and bond dipole are in the same direction

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Solution:

(a) In $N H_{3}$ the atomic dipole and bond dipole are in the same direction whereas in $N F_{3}$ these are in opposite direction so in the former case they are added up whereas in the latter case net result is reduction of dipole moment. It has been shown in the following figure :

Chemical Bonding and Molecular Structure - Result Question 29

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Chemical Bonding and Molecular Structure - Result Question 29

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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