SATHEE: Chemical Bonding and Molecular Structure

Chemical Bonding and Molecular Structure - Result Question 122

####126. The ground state electronic configuration of valence shell electrons in nitrogen molecule $(N_{2})$ is written as $K K σ 2 s^{2}, σ^{*} 2 s^{2}, π 2 p_{x}^{2}, π 2 p_{y}^{2} σ 2 p_{z}^{2}$ Bond order in nitrogen molecule is

[1995]

(a) 0

(b) 1

(d) 3

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Solution:

(d) In this configuration, there are four completely filled bonding molecular orbitals and one completely filled antibonding molecular orbital. So that $N_{b} = 8$ and $N_{a} = 2$ .

$∴$ Bond order $= \frac{1}{2} (N_{b} - N_{a}) = \frac{1}{2} (8 - 2) = 3$ .

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Chemical Bonding and Molecular Structure - Result Question 122

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