SATHEE: Chemical Bonding and Molecular Structure

Chemical Bonding and Molecular Structure - Result Question 12

####12. Among $L i C l, B e C l_{2} B C l_{3}$ and $C C l_{4}$ , the covalent bond character follows the order

[1990]

(a) $L i C l < B e C l_{2} > B C l_{3} > C C l_{4}$

(b) $B e C l_{2} < B C l_{3} < C C l_{4} < L i C l$

(d) $L i C l > B e C l_{2} > B C l_{3} > C C l_{4}$

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Solution:

(c) As we move in period from $L i \to B e \to$ $B \to C$ , the electronegativity $(E N)$ increases and hence the EN difference between the element and $C l$ decreases and accordingly the covalent character increases.Thus $L i C l < B e C l_{2} < B C l_{3} <$ $C C l_{4}$ is correct.

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Chemical Bonding and Molecular Structure - Result Question 12

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