Chemical Bonding and Molecular Structure - Result Question 12
####12. Among $LiCl, BeCl_2 BCl_3$ and $CCl_4$, the covalent bond character follows the order
[1990]
(a) $LiCl<BeCl_2>BCl_3>CCl_4$
(b) $BeCl_2<BCl_3<CCl_4<LiCl$
(c) $LiCl<BeCl_2<BCl_3<CCl_4$
(d) $LiCl>BeCl_2>BCl_3>CCl_4$
Show Answer
Solution:
- (c) As we move in period from $Li \to Be \to$ $B \to C$, the electronegativity $(EN)$ increases and hence the EN difference between the element and $Cl$ decreases and accordingly the covalent character increases.Thus $LiCl<BeCl_2<BCl_3<$ $CCl_4$ is correct.
