Chemical Bonding and Molecular Structure - Result Question 110

####113. According to MO theory which of the following lists ranks the nitrogen species in terms of increasing bond order?

[2009]

(a) N22<N2<N2

(b) N2<N22<N2

(c) N2<N22<N2

(d) N2<N2<N22

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Solution:

  1. (a) Molecular orbital configuration of

$N_2^{2-}=\sigma 1 s^{2} \sigma^{} 1 s^{2} \sigma 2 s^{2} \sigma^{} 2 s^{2}-$

$ {\begin{array} { l } { \pi 2 p _ { y } ^ { 2 } } \ { \pi 2 p _ { z } ^ { 2 } } \end{matrix} \sigma \sigma 2 p _ { x } ^ { 2 } {π2py1π2pz1 .. $

Bond order =1062=2

$N_2^{-}=\sigma 1 s^{2} \sigma^{} 1 s^{2} \sigma 2 s^{2} \sigma^{} 2 s^{2}$

$ {\begin{array} { l } { \pi 2 p _ { y } ^ { 2 } } \ { \pi 2 p _ { z } ^ { 2 } } \end{matrix} \quad \sigma 2 p _ { x } ^ { 2 } {π2py1π2pz0 .. $

Bond order =1052=2.5

$N_2=\sigma 1 s^{2} \sigma^{} 1 s^{2} \sigma 2 s^{2} \sigma^{} 2 s^{2}{π2py2π2pz2 , \sigma 2 p_x^{2}.$

Bond order =1042=3

The correct order is =N22<N2<N2



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